If x2+y2=34 and xy=10 1/2 then find 2(x+y)^2+(x-y)^2[ ICSE Class 9 S.Chand (Fundamentals of Mathematics) Chapter 3 Exercise-3.1 Question Number 16 Solution Expansion and Factorisation]
2(x+y)2+(x-y)2
= 2(x2+2xy+y2)+(x2-2xy+y2)
=2(x2+y2+2xy)+(x2+y2-2xy)
=2(x2+y2) +4xy+ (x2+y2) -2xy
= 3(x2+y2)+2xy
= 3×34 +2 × $10\frac{1}{2}$
= 102 + 2 × $\frac{21}{2}$
=102 +21
= 123
Therefore 2(x+y)2+(x-y)2 = 123