Evaluate: (i) 305^2 +295^2 (ii) (2a^3+b^2c^5)^2-(2a^3-b^2c^5)^2

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Evaluate: (i) 305^2 +295^2 (ii) (2a^3+b^2c^5)^2-(2a^3-b^2c^5)^2

(i) 3052 + 2952

= (300+5)2 +(300-5)2

= (300)2 +2 . 300 . 5 +(5)2 +(300)2-2.300.5 +(5)2

= (300)2 +(300)2+(5)2+(5)2

= 2{(300)2+(5)2}

=2(90000+25)

= 2 x 90025

= 180050 [Ans]

(ii) (2a3+b2c5)2-(2a3-b2c5)2

= (2a3+b2c5+2a3-b2c5)(2a3+b2c5-2a3+b2c5)

= 4a3 x 2b2c5

= 8a3b2c5 [Ans]

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