Prove that, sinα +sin(120°+α) + sin(240°+α) = 0
Solution: sinα +sin(120°+α) + sin(240°+α) = sinα+ 2 sin $\frac{(120° + {\mathrm{\alpha}} + 240°+ {\mathrm{\alpha}})}{2}$ cos$\frac{(120° + {\mathrm{\alpha}} – 240° …
Solution: sinα +sin(120°+α) + sin(240°+α) = sinα+ 2 sin $\frac{(120° + {\mathrm{\alpha}} + 240°+ {\mathrm{\alpha}})}{2}$ cos$\frac{(120° + {\mathrm{\alpha}} – 240° …