আমাদের টেলিগ্রাম চ্যানেলে যুক্ত হোন

Limit x Tends to 0 (tan x-sin x)/(1-cos x)|$\lim_{x\rightarrow 0}\frac{\tan x – sinx}{1 – cosx}$

by
Limit x Tends to 0 (tan x-sin x)/(1-cos x)
$\lim_{x\rightarrow 0}\frac{\tan x – sinx}{1 – cosx}$
= $\lim_{x\rightarrow 0}\frac{\sin x\left(\frac{1}{\cos x} – 1\right)}{1 – cosx}$
=$ \lim_{x\rightarrow 0}\frac{\sin x\left(\frac{1 – cosx}{\cos x}\right)}{1 – cosx}$
= $\lim_{x\rightarrow 0}\frac{\sin x(1 – cos x)}{\cos x(1 – cos x)}$
= $\lim_{x\rightarrow 0}tanx$
= 0

আরও দেখুন

  1. Evaluate Limit x tends to 0 (tanx-sinx)/x^3|$\lim_{x\rightarrow 0}\frac{\tan x – sinx}{x^3}$
  2. Limit x Tends to Zero $\lim_{x\rightarrow 0}\frac{1 – cosx}{x^2}$
  3. Limit x Tends to Zero $\lim_{x\rightarrow 0}\frac{1 – cosx}{\sin^2x}$
  4. Limit x Tends to Zero $\lim_{x\rightarrow 0}\frac{xtanx}{1 – cosx}$
  5. Evaluate: Limit x tends to zero (cosx-secx)/x^2||$\lim_{x\rightarrow 0}\frac{\cos x – secx}{x^2}$

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