আমাদের টেলিগ্রাম চ্যানেলে যুক্ত হোন

Limit x Tends to Zero $\lim_{x\rightarrow 0}\frac{1 – cosx}{\sin^2x}$

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Limit x Tends to Zero $\lim_{x\rightarrow 0}\frac{1 – cosx}{\sin^2x}$

$\lim_{x\rightarrow 0}\frac{1 – cosx}{\sin^2x}$
= $\lim_{x\rightarrow 0}\frac{(1 – cos x )(1 + cos x)}{\sin^2x(1 + cos x)}$
= $\lim_{x\rightarrow 0}\frac{1 – cos^2x}{\sin^2x(1 + cosx)}$
= $\lim_{x\rightarrow 0}\frac{\sin^2x}{\sin^2x(1 + cosx)}$
= $\lim_{x\rightarrow 0}\frac{1}{1 + cosx}$
= $\frac{1}{1 + 1}$
= $\frac{1}{2}$

আরও দেখুন

  1. Limit x Tends to Zero $\lim_{x\rightarrow 0}\frac{1 – cosx}{x^2}$
  2. Limit x Tends to Zero $\lim_{x\rightarrow 0}\frac{xtanx}{1 – cosx}$
  3. Limit X Tends to Zero $\lim_{x\rightarrow 0}\frac{1 – cos4x}{x^2}$
  4. Limit h Tends to 0 $\lim_{h\rightarrow 0}\frac{\cos ah – cosbh}{h^2}$
  5. Limit h tends to zero $\lim_{h\rightarrow 0}\frac{1 – cosh}{hsinh}$

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