Prove that,4 sin15° sin75°=$\sqrt{2}$ (cos 105° + sin75°)
Prove that,4 sin15° sin75°=$\sqrt{2}$ (cos 105° + sin75°) L.H.S: 4 sin15° sin75° = 2 (2 sin15° sin75°) = 2{cos(15°+75°)+cos(15°-75°)} =2 …
Prove that,4 sin15° sin75°=$\sqrt{2}$ (cos 105° + sin75°) L.H.S: 4 sin15° sin75° = 2 (2 sin15° sin75°) = 2{cos(15°+75°)+cos(15°-75°)} =2 …