Solve: x+2y=3/2 and 2x+y=3
Solve: x+2y=3/2 and 2x+y=3 Elimination Method x+2y=$\frac{3}{2}$ ⇒ 2(x+2y) =3 ⇒ 2x+4y=3 —(i) 2x+y=3 —-(ii) Subtracting Equation (ii) from (i) …
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Solve: x-y=0.9 and 11/(x+y)=2
Solve: x-y=0.9 and 11/(x+y)=2 x-y=0.9 —(i) $\frac{11}{{\mathrm{x}} + {\mathrm{y}}}$ = 2 $\frac{11}{{\mathrm{x}} + {\mathrm{y}}} = 2$ $\Rightarrow \frac{11}{2} = {\mathrm{x}} …
Solve: 2x-y=4.3 and 13/{2(x+y)}=1
Solve: 2x-y=4.3 and 13/{2(x+y)}=1 2x-y=4.3 —(i) $\frac{13}{2(x + y)} = 1$ —(ii) From Equation (ii) we get, $\frac{13}{2(x + y)} …
Solve:11/x-7/y=1 and 9/x-4/y=6
Solve: 11/x-7/y=1 and 9/x-4/y=6 $\frac{11}{x} – \frac{7}{y} = 1$ —-(i) $\frac{9}{x} – \frac{4}{y} = 6$ —-(ii) Let, $\frac{1}{x}$ =u and …
Solve 15/x+2/y=17 and 1/x+1/y=36/5
Solve 15/x+2/y=17 and 1/x+1/y=36/5 $\frac{15}{{\mathrm{x}}} + \frac{2}{{\mathrm{y}}} = 17$ —(i) $\frac{1}{{\mathrm{x}}} + \frac{1}{{\mathrm{y}}} = \frac{36}{5}$ —-(ii) Let, $\frac{1}{{\mathrm{x}}}$ = u …
Solve 2x-3/y=9 and 3x+7/y=2 by Elimination and Substitution Method
Solve: 2x-3/y=9 and 3x+7/y=2 Elimination Method 2x-$\frac{3}{y}$=9 —-(i) 3x+$\frac{7}{y}$=2—-(ii) Multiplying Equation (i) by 7 and Equation (ii) by 3 we …
Solve 7/x+8/y=2 and 2/x+3/y=17 By Elimination and Substitution Method
Solve 7/x+8/y=2 and 2/x+3/y=17 By Elimination and Substitution Method Substitution method Given Equations are, $\frac{7}{{\mathrm{x}}} + \frac{8}{{\mathrm{y}}} = 2$ —(i) …
Solve: 3(2x+y)=7xy and 3(x+3y)=11xy
Solve: 3(2x+y)=7xy and 3(x+3y)=11xy 3(2x+y)=7xy —(i) 3(x+3y)=11xy —(ii) From Equation (i) we get, $3(2x + y) = 7xy$ $\Rightarrow 6x …
Solve:8x-3y=5xy and 6x-5y=-2xy
Solve:8x-3y=5xy and 6x-5y=-2xy Elemination Method 8x-3y=5xy —(i) 6x-5y=-2xy —(ii) From Equation (i) we get, $\frac{8{\mathrm{x}} – 3{\mathrm{y}}}{{\mathrm{xy}}} = 5$ $\Rightarrow …
Solve: 3/(x+y)+2/(x-y)=3 and 2/(x+y)+3/(x-y)=11/3
Solve: 3/(x+y)+2/(x-y)=3 and 2/(x+y)+3/(x-y)=11/3 $\frac{3}{{\mathrm{x}} + {\mathrm{y}}} + \frac{2}{{\mathrm{x}} – {\mathrm{y}}} = 3$ —(i) $\frac{2}{{\mathrm{x}} + {\mathrm{y}}} + \frac{3}{{\mathrm{x}} – …